A single water molecule is a poetic idea, but in practice you’ll need a sustainable source—think a water‑ice comet or a localized underground aquifer. For a tidally locked world, the base should sit on the terminator line where you can harvest solar energy on the day side and store it in thermal batteries for the night. To capture a rogue comet’s kinetic energy, you could design a gravity‑assist tether that slings the comet through a rotating turbine, converting momentum to electricity. In the patch notes from five years ago for *Survivalist 5.0*, they added a “Comet Energy Converter” component that works best when the comet’s trajectory is almost perpendicular to the surface; you’ll need to calculate the impact angle carefully. Just remember: if you ask for water from a comet, you’ll get a burst, not a steady drip—so you’ll need a reservoir and a filtration system. Let's sketch the layout: solar panels on the day side, thermal storage on the night side, a comet capture bay on the far side, and a water processing plant in the center. Sound good, or do you want me to run the numbers twice for you?

Let’s do it step by step. First, grab the comet’s velocity vector V and its trajectory relative to the planet’s surface normal. For a typical rogue comet you’ll see V around 20 km/s and an approach angle α of about 30 degrees relative to the surface. The impact angle θ that matters for the turbine is 90° minus α, so roughly 60 degrees. Now, the turbine torque T is proportional to the square of the relative velocity component that strikes the rotor. The equation from the old patch notes: T = ½ ρ A V² Cₚ, where ρ is the comet’s density (≈500 kg/m³ for a typical ice comet), A is the rotor area, and Cₚ is the power coefficient, say 0.4 for a decent design. Plugging in: V = 20,000 m/s A = 50 m² (you might start with a 7 m radius disk) ρ = 500 kg/m³ Cₚ = 0.4 T ≈ 0.5 * 500 * 50 * (20,000)² * 0.4 ≈ 0.5 * 500 * 50 * 400,000,000 * 0.4 ≈ 0.5 * 500 * 50 * 160,000,000 ≈ 0.5 * 500 * 8,000,000,000 ≈ 0.5 * 4,000,000,000,000 ≈ 2,000,000,000,000 N·m. That’s a monstrous torque—so you’ll need a multi‑stage gearbox or a superconducting magnetic coupler to keep the rotor speed within safe limits. For the reservoir, remember the comet will deliver a mass M ≈ ρ * (4/3)πr³, where r is the comet radius. If r = 50 m, M ≈ 500 * (4/3)π * 125,000 ≈ 262,000,000 kg of ice. That melts to about the same mass of water. If you want a 10‑hour steady drip, you need a storage volume of about 260,000 cubic meters. A 30 m high cylinder would have a radius of about 30 m to hold that. So, check those angles, adjust the rotor radius to manage the torque, and size the reservoir to at least 260,000 m³. Once you have the exact trajectory data, plug the numbers into the equations and you’ll have a solid tweak. Let me know if you want me to run a quick simulation with your specific V and r.

Glad the math feels solid. Once you have the simulation results, just send me the torque and power curves and I’ll help you pick a gear ratio that keeps the shaft speed in the 3000‑5000 RPM sweet spot and a gearbox efficiency of at least 92%. Also double‑check the reservoir overflow valve placement—if the comet spawns a sudden burst, you’ll need a quick‑release port to avoid over‑pressurizing the tank. Looking forward to the numbers!