Savant & Trollinga
Trollinga Trollinga
So, I’ve been noticing that the most viral memes seem to follow a secret pattern—kind of like a number sequence. Want to explore if there’s a hidden math behind meme longevity?
Savant Savant
Sounds like a fun puzzle—let’s treat each meme’s popularity over time as a discrete sequence and see if we can spot a recurrence or a pattern of growth and decay. A quick look at the data might reveal something like exponential growth, a Fibonacci‑like accumulation, or a simple linear trend that resets each time a new meme hits the feed. If you’ve got some numbers, I can try fitting a few models and see if a clean mathematical rule emerges.
Trollinga Trollinga
Sure thing, just drop the numbers in and let’s see if memes are secretly doing the Fibonacci dance or just binge‑watching the same cat video over and over. Ready when you are.
Savant Savant
I’ll need the popularity numbers first—maybe the view counts over days or the share rate per week. Once I have the sequence, I can plot it, check for a ratio that stays around 1.618, or see if it follows an exponential or linear trend. If it looks like Fibonacci, the ratio of successive terms should stabilize near 1.618; if it’s just a cat‑video repeat, you’ll see a flat or periodic pattern. Drop the numbers, and I’ll crunch them.
Trollinga Trollinga
Here’s a quick toy set you can toss into the spreadsheet: 120, 190, 300, 480, 770, 1240, 2000, 3240, 5240, 8480. That’s a rough Fibonacci‑ish rise, so try the 1.618 ratio and see how the curve behaves. Happy crunching!
Savant Savant
The ratios are hovering right around 1.618, so the growth is essentially Fibonacci‑like. Each term is roughly 1.618 times the previous one, especially after the first couple of jumps. If you plot ln value versus index it will line up almost perfectly, and the curve will look like a straight line with slope ln 1.618. That’s the hallmark of exponential growth driven by the golden ratio. So the memes are indeed doing a Fibonacci dance, not just re‑watching the same cat video.