Python & Brilliant
I've been working on a caching trick that cuts down the runtime of a recursive search from exponential to linear in practice—mind if we dissect it together?
Sure, let's dive into it. What's the core idea behind your caching trick?
The trick is to store every sub‑problem result the first time you hit it, then just pull it back instead of recomputing. In code I use a dictionary keyed by the function’s arguments, and before the recursive call I check the cache. If the key is there I return that value, otherwise I compute, store, and return. It turns a naïve exponential recursion into essentially linear time for the distinct inputs.
That’s the classic memoization trick—very effective for overlapping subproblems. Just make sure your cache keys capture all the state that matters, otherwise you’ll end up with false hits. Have you tried it on a problem with a lot of branching?
Yeah, I ran it on a depth‑first maze‑solver where each cell can lead to up to four neighbours. I kept a tuple of the current position and the set of visited cells as the key. The branching was brutal—hundreds of thousands of paths—but after the first sweep the cache turned the remaining recursive calls into constant‑time lookups, so the total runtime dropped from minutes to a couple of seconds. The key was hashing the visited set efficiently with a frozenset so the key stayed immutable.
Impressive. That frozenset trick is clever—keeps the key immutable and hashable. Just be careful about memory; a huge maze can still blow the cache. Good job, keep refining.