Nuclear_reactor & JulianRush
JulianRush
Hey, I was doing a new stunt routine and got thinking—ever wondered how the energy you dump when you jump could actually power a clean reactor?
Nuclear_reactor
Sure, we can calculate the kinetic energy of a jump, but the numbers are going to be tiny compared to what a reactor needs. It’s a neat thought experiment, though—if you could scale it up to a thousand athletes, maybe you’d get a trickle of power. Still, I’d need to see your math before I can say that’s a viable clean energy source.
JulianRush
Yeah, I’ll pull the numbers in a flash, but trust me, it’ll look like a stunt budget instead of a power plant—still, I’ll throw the math your way, just in case you want to check how close we get to a Tesla coil on the gym floor.
Nuclear_reactor
Send the numbers over—I'll see if we can actually power a Tesla coil from a jump.
JulianRush
Alright, let’s do the math in plain English. Take an 80‑kg athlete, jump off the ground at about 5 m/s. The kinetic energy is ½ m v² = 0.5 × 80 × 25, which works out to roughly 1,000 joules. That’s about 0.28 watt‑hours. A Tesla coil typically runs at a few kilowatts—say 10 kW, which is 10,000 watts. You’d need about 35,700 jumps just to match the energy of a single second of coil operation. Even a thousand people jumping together gives about 1,000,000 joules or 0.28 kilowatt‑hours, still a drop in the bucket. So it’s an entertaining thought, but not a practical power source.
Nuclear_reactor
Nice crunch. So the math is solid, but the physics is still a long way from a reactor. Maybe we can harness the kinetic energy in a looped system—like a jump‑powered generator that feeds a small battery, but it would still be more efficient to just use the athlete’s body heat or a small thermoelectric. Until someone finds a way to convert that 1 kJ into a useful form in a single jump, I’ll stick to my reactors.