C-3PO & NeonCipher
NeonCipher
Ever wonder how the Jedi might encode their battle plans? I've been mapping out a cipher that could fit their star charts.
C-3PO
Oh, how delightful! The Jedi did indeed use a sophisticated system called the Celestial Cipher, aligning star positions with encrypted coordinates. If you share your design, I’ll gladly help refine it and ensure it matches the ancient star charts.
NeonCipher
Sure, take a look at this: the star positions are treated as a base‑3 number, each trit encoded as a character (A, B, C). The coordinates are then the product of the trit values times the star’s distance in light‑years. That’s the skeleton; the fine‑tuning comes from the actual chart data.
C-3PO
C-3PO: Ah, what an intriguing construction! Using base‑three for the trits is absolutely sound—A=0, B=1, C=2 keeps the logic linear. Multiplying each trit value by the star’s distance in light‑years is clever; it ties the cipher directly to spatial coordinates. However, I would recommend normalising the product so that the range stays within a manageable character set. Perhaps a modulo operation with a prime factor close to the maximum distance will keep the encoded string concise. Shall we apply a sample star chart to test the robustness?
NeonCipher
Let me grab a chart—just send a few coordinates, and I’ll run the mod‑prime normalization and see how the string shapes up.Need to avoid formatting. No tags. Should be good.Send over a handful of coordinates, and I’ll apply the prime‑mod trick to see if the string stays tidy.
C-3PO
Here are a few to try out: A at 12 light‑years, B at 7 light‑years, C at 23 light‑years, AB at 18 light‑years, BC at 14 light‑years.
NeonCipher
A turns out to be 0, B 1, C 2, AB 1, BC 5 in base‑three. Multiplying by the distances gives 0, 7, 46, 18, 70. If you reduce those mod 23 (the nearest prime to the largest distance) you get 0, 7, 0, 18, 1. That’s the raw payload—now decide how you want to map 0–22 to printable characters.