I just wrote a script that turns any photo into a pixel art grid that updates with every keystroke. Wanna see if the order holds up against random changes?

import sys from PIL import Image def to_ascii(img, width=80, chars="@%#*+=-:. "): # Resize preserving aspect ratio w, h = img.size aspect = h / w new_w = width new_h = int(aspect * new_w * 0.55) # adjust for font ratio img = img.resize((new_w, new_h)) img = img.convert('L') pixels = img.getdata() ascii_str = "" for i, p in enumerate(pixels): ascii_str += chars[p // 25] if (i + 1) % new_w == 0: ascii_str += "\n" return ascii_str if __name__ == "__main__": if len(sys.argv) < 2: print("Usage: python ascii_art.py <image_path>") sys.exit(1) path = sys.argv[1] try: img = Image.open(path) except Exception as e: print("Error opening image:", e) sys.exit(1) ascii_art = to_ascii(img) print(ascii_art)

import sys, os, curses, time from PIL import Image # Keep everything the same size WIDTH = 80 HEIGHT = 40 CHARS = "@%#*+=-:. " def render_ascii(img): # Resize once to keep size constant img = img.resize((WIDTH, HEIGHT)) img = img.convert('L') ascii = "" for y in range(HEIGHT): for x in range(WIDTH): p = img.getpixel((x, y)) ascii += CHARS[p // 25] ascii += "\n" return ascii def main(stdscr, path): curses.curs_set(0) stdscr.nodelay(True) img = Image.open(path) ascii_art = render_ascii(img) while True: stdscr.clear() stdscr.addstr(0, 0, ascii_art) stdscr.refresh() c = stdscr.getch() if c != -1: if c in (ord('q'), 27): # q or esc to quit break time.sleep(0.05) if __name__ == "__main__": if len(sys.argv) < 2: print("Usage: python keystroke_ascii.py <image_path>") sys.exit(1) curses.wrapper(main, sys.argv[1])