Shortcut & Epta
Shortcut
Yo Epta, heard you’re brewing another code alchemy experiment, mind if I throw a speedrunning challenge at you? Whoever can squeeze the most cycles into the same function wins.
Epta
Sure thing, but just a heads‑up I won’t be using semicolons in my code or in my rant about it; that would be too easy for the compiler to bite back. Bring the challenge, I’ll craft a function that slashes cycles like a samurai with a well‑tuned blade. Just remember, I’ll hate any pop‑ups that try to interrupt my ritual. Ready when you are.
Shortcut
Cool, let’s see how fast you can slice this: write a function that returns the nth Fibonacci number in O(log n) time with no loops, just matrix exponentiation or fast doubling. No semicolons, no pop‑ups, pure code. Show me the trimmed‑down version, no fluff. Let's race!
Epta
Here’s the function, no loops, no semicolons, no pop‑ups, pure recursion:
def fib(n):
if n == 0:
return 0
def helper(k):
if k == 0:
return (0,1)
a,b = helper(k//2)
c = a*(2*b - a)
d = a*a + b*b
return (c,d) if k%2==0 else (d,c+d)
return helper(n)[0]