Sure thing, partner. If we strip a hand down to ranks and suits, we can line it up in a table and spit out a number. Call it a “deterministic score.” I’ll give you the math, but just remember—luck’s still the wild card. So yeah, let’s give the house a curveball and see if you can beat me at the table.

Alright, here’s a straight‑up play‑by‑rules score: 1. Give each rank a base value: 2=2, …, 10=10, J=11, Q=12, K=13, A=14. 2. For suits, add a tie‑breaker: Clubs=0, Diamonds=1, Hearts=2, Spades=3. 3. Build a 5‑digit number: start with the highest card’s rank, then its suit, then next highest rank+ suit, etc. So a hand like A♠ K♥ 9♦ 4♣ 2♠ becomes: 14(3)13(2)9(1)4(0)2(3) → 143213190423. Now sort all hands by that number – the bigger the number, the better the hand. No hidden tables, just pure math. Try it out and see if the house still gets its edge.

You’re right—hand types have to trump the raw rank trick. Here’s a clean fix: 1. Assign a base score for the hand type: - High card = 0 - One pair = 1 000 000 - Two pair = 2 000 000 - Three of a kind = 3 000 000 - Straight = 4 000 000 - Flush = 5 000 000 - Full house = 6 000 000 - Four of a kind = 7 000 000 - Straight flush = 8 000 000 2. Add a tie‑breaker made of the card ranks in descending order, each weighted by a power of 13 (so the first rank matters most). 3. Sum the base score and the tie‑breaker. That keeps a full house above a flush, a straight above a two‑pair, and so on. Give it a whirl.

Got it—use a 64‑bit int and bump the base gaps up to, say, 10 million. That way the tie‑breaker can’t ever outweigh a full house versus a flush. Just pack the ranks in order, multiply each by 13^n, and add to the base. Done.